If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((2x^2)/25)=18
We move all terms to the left:
((2x^2)/25)-(18)=0
We get rid of parentheses
2x^2/25-18=0
We multiply all the terms by the denominator
2x^2-18*25=0
We add all the numbers together, and all the variables
2x^2-450=0
a = 2; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·2·(-450)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*2}=\frac{-60}{4} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*2}=\frac{60}{4} =15 $
| 2|4-3x|=2 | | Y+2y=1.6 | | 5x-27=x+13 | | 2(2w+3)+w=9w | | (2x^2)/25=18 | | 4f=6 | | (7x÷2)-3=18 | | 7x÷2-3=18 | | 12a+6=54 | | -4(3-5x)=48 | | 0.2x+3=0.1+0.7 | | 3x+8=3(x-3)-2 | | 11/9y-12=1 | | 2(-15/4)+4a=7 | | 3(2x-5)-5=3(x-5)+22 | | (x-16)(28)=180 | | 2x=5=3x+1 | | -8x+1/3x-x/3=0 | | 10y+5=405 | | 7x-7=-7(1-x) | | 15-3(4m+6)+14=2m-3 | | 5x(3+2)=86-9 | | V^2+7v-13=-5 | | 10y5=405 | | 2x+5=3x=1 | | 7+3m=-12 | | (x-16)+(6x)=180 | | 5(3x+4)=21+15x | | N^212n+32=0 | | 5x(5)=77 | | (x−5)−17=17−(x−5) | | -7=18-5r |